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Friday, November 11, 2011

PEE-3

State and explain Faraday's law of electromagnetic induction.
Ans :-
Faraday gave the following two laws…………
FIRST LAW :- It states whenever the magnetic flux linked with a coil
or circuit changes, an e.m.f. is always induced in it. This e.m.f. is
exist in the circuit or coil as long as the changes in magnetic flux
continues.
OR
It states, whenever a conductor cuts magnetic flux, an e.m.f. is
induced in that conductor.
SECOND LAW :- It states, the magnitude of induced e.m.f. is directly
proportional to the rate of change of magnetic flux linked with the
circuit or coil.
We may also say that the magnitude of induced e.m.f. is equal to
the rate of change of flux-linkages.
EXPLANATION :-
Suppose a coil has N turns & flux through it changes from an
initial value of Ø₁   webers to the final value of Ø webers in time t
seconds. Then, we have ( from Faraday's Law )………………
Initial flux linkages = NØ and
Final flux linkages = NØ
So rate of change of magnetic flux
OR
induced e.m.f. ( e ) = ( NØ - NØ )/t wb/second or volt or
e = N( Ø - Ø )/t volt
Putting the above expression in its differential form, we have
e = d/dt ( NØ ) = N(d∅)/dt volt
Usually, a minus sign is given to the right-hand side expression
to signify the fact that the induced e.m.f. sets up current in such a
direction ( to oppose the change in flux ) that magnetic effect
produced by it opposes the very cause producing it.
So, e = - N(d∅)/dt volt .